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Mathematics 8 Online
OpenStudy (anonymous):

Prove that the opposite angles of a parallelogram are congruent.

OpenStudy (anonymous):

OpenStudy (anonymous):

Is it multiple choice or what?

OpenStudy (anonymous):

use properties of angles of parallel lines cut by a transversal im betting that would be the quickest way to prove it

OpenStudy (anonymous):

Well the definition of a parallelogram states that you have 2 pairs of parallel sides, hence <A + <B = <B + <C = 180. Because of that property, we have <A + <B = <B + <C, and a simple cancellation of <B will tell us that <A = <C

OpenStudy (anonymous):

@FutureMathProfessor ooo so you would use the definition of a parallelogram to prove it and that is it?

OpenStudy (anonymous):

It's all you have to use. No need in overcomplicating things.

OpenStudy (anonymous):

@FutureMathProfessor o k so my answer would be similar to the thing you wrote?

OpenStudy (anonymous):

AB|| DC and BD cuts it. \[<2=<4 ....(Alternating angles.)\] <6=<5 ....(Alternating angles) <2+<6=<4+<5 <ADC=<ABC Similarly we can prove <BCD=<<BAD

OpenStudy (anonymous):

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