Question

How to simplify this expression:
(2x/x^2-6x+9) - (1/x+1) - (8/x^2-2x-3)

Answer 1

\[\frac{ 2x }{ x^2-6x+9 } - \frac{ 1 }{ x+1 } - \frac{ 8 }{ x^2-2x-3 }\]

Answer 2

2x / x^2 =
2/x
(2/x - 6x + 9) -(1/x +1) - (8/x^2 -2x -3)

Next distribute the negative signs in front of (1/x + 1) and -(8/x^2 -2x -3)

Answer 3

The denominators of the first and last term can be factored, have you tried doing that yet? :D

Answer 4

I was able to solve it. Thanks!