As a 2.0-kg block travels around a 0.50-m radius circle it has an angular speed of 12 rad/s.The circle is parallel to the xy plane and is centered on the z axis, 0.75 m from the origin. The magnitude of its angular momentum around the origin is ?

Question

anonymous · Answer

I=mr^2 : (2)(.5)^2 =.5
L=IW = .5(12)=6  , but the answer was 11 !

anonymous · Answer

@theEric  , can you  help me Plz ?

theeric · Answer

I don't see the problem. I might be missing something, but I agree with you!

anonymous · Answer

but the correct answer was 11 ! there is somethig wrong :D

theeric · Answer

Maybe some other people will have input! Otherwise, maybe the answer was written incorrectly. Textbooks do that sometimes.

anonymous · Answer

Ok , However thank you :)

theeric · Answer

Not a problem! Good luck!

vincent-lyon.fr · Answer

The answer is 10.8 kg.m².s-1

You have calculated the angular momentum about the centre of the circle, and the problem asks you to calculate it about the origin.

theeric · Answer

Well, I should have read it better! That would explain why it gave the information about it in the plane! I'm going to come back later and try to attain this answer for myself!