Question

solve the system of linear equations
2x+3y=2
x+6y=4

Answer 1

what does x equal on the bottom equation

Answer 2

i dont know

Answer 3

firstm ultiply the bottom equation to get the x's cancle out with -2 so you got
2x+3y=2
-2x-12y=-8

the x's cancel and you get

-9y=-6

divide by -9 and you get

\[y=\frac{ 2 }{ 3 }\]

do same for y or just plug in 2/3 into one the equations to get y.

Answer 4

i mean to get x not y

Answer 5

how did you get -2

Answer 6

you mean how did i come up with multiplying by -2?

Answer 7

yes

Answer 8

well look at both lines
2x+3y=2
x+6y=4
you want one the variables to cancel out by multiplying by an umber on one or both lines. The easiest way is to multiply the 2nd by -2 so you have 2x in first line and -2x in 2nd line. They both cancel each other and you got only a y variable and what it equals to xsolve for y.

Answer 9

so by putting -2x it cancel 2x
so -2 would not change the whole equation -2x+12y=8

Answer 10

not exactly if your multiply a number into the line you multiply each term so it becomes
-2x-12y=-8

Answer 11

oh yea forgot about the negative

Answer 12

yea but if you get -2x-12y=-8 and line the lines up again:
2x+3y=2
-2x-12y=-8
notice the 2x and -2x cancel and combine the rest you get -9y=-6 and solve for y.