Ill give a medal to who ever answers. [9.01] Determine whether the graph of y = −3x2 + 2x − 8 opens up or down and whether it has a maximum or minimum point. Up; Minimum Up; Maximum Down; Minimum Down; Maximum
it is a quadratic, so a parabola the leading coefficient is negative (it is \(-3\)) and therefore it opens DOWN
since it opens down, it has a maximum, but no minimum
Oh ok thanks
yw
you mind answering another one?
Oh no I just missed a medal!!!
lol
no i don't mind, go ahead and post
[9.01] Identify the vertex for the graph of y = −3x2 + 6x − 2. (1, 1) (−1, 1) (1, −5) (−1, −5)
I think it is (-1, -5)
first coordinate of the vertex is always \(-\frac{b}{2a}\) which in your case is \[-\frac{6}{2\times (-3)}=1\]
ok then, i still think im right on the -5 though
second coordinate of the vertex is what you get when you replace \(x\) by the first coordinate
no, it is not \(-5\)
oh ok
if you let \(x=1\) you get \(-3+6-2\)
so 1
so vertex is \((1,1)\)
ok thanks! :)
yw
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