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Mathematics 17 Online
OpenStudy (anonymous):

What must be true in order for P (A or B) = P(A) + P (B)?

OpenStudy (anonymous):

would they we dependent or independent

OpenStudy (goldeverything):

dependent

OpenStudy (anonymous):

okay. thank you

OpenStudy (goldeverything):

your welcome anytime

OpenStudy (anonymous):

would that be the same as disjoint?

OpenStudy (anonymous):

hold the phone!

OpenStudy (anonymous):

here are my options A and B cannot be disjoint. A and B must be independent. A and B cannot be independent. A and B must be disjoint. It is always true.

OpenStudy (anonymous):

it has nothing to do with "independence" at all if \(P(A\cup B)=P(A)+P(B)\) then \(P(A\cap B)=0\)

OpenStudy (anonymous):

if \(P(A\cap B)=0\) then in most cases \(A\cap B=\emptyset\) and so \(A\) and \(B\) are "disjoint"

OpenStudy (anonymous):

what does disjoint even mean? does it mean equal to 0?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

disjoint means there is nothing in \(A\cap B\)

OpenStudy (anonymous):

oh okay!

OpenStudy (anonymous):

sets are not equal to zero probabilities are equal to zero

OpenStudy (anonymous):

this makes my next problem easier

OpenStudy (anonymous):

thank you so much

OpenStudy (anonymous):

example, if \(A=\{a,b\}\) and \(B=\{c,d\}\) then \(A\cap B=\emptyset\) i.e. there is nothing in the intersection

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

oh okay, just to clarify, What would happen with the same problem if I multiplied p(a) and p(b)

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