What must be true in order for P (A or B) = P(A) + P (B)?
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OpenStudy (anonymous):
would they we dependent or independent
OpenStudy (goldeverything):
dependent
OpenStudy (anonymous):
okay. thank you
OpenStudy (goldeverything):
your welcome anytime
OpenStudy (anonymous):
would that be the same as disjoint?
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OpenStudy (anonymous):
hold the phone!
OpenStudy (anonymous):
here are my options
A and B cannot be disjoint.
A and B must be independent.
A and B cannot be independent.
A and B must be disjoint.
It is always true.
OpenStudy (anonymous):
it has nothing to do with "independence" at all
if \(P(A\cup B)=P(A)+P(B)\) then \(P(A\cap B)=0\)
OpenStudy (anonymous):
if \(P(A\cap B)=0\) then in most cases \(A\cap B=\emptyset\) and so \(A\) and \(B\) are "disjoint"
OpenStudy (anonymous):
what does disjoint even mean? does it mean equal to 0?
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
disjoint means there is nothing in \(A\cap B\)
OpenStudy (anonymous):
oh okay!
OpenStudy (anonymous):
sets are not equal to zero
probabilities are equal to zero
OpenStudy (anonymous):
this makes my next problem easier
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OpenStudy (anonymous):
thank you so much
OpenStudy (anonymous):
example, if \(A=\{a,b\}\) and \(B=\{c,d\}\) then \(A\cap B=\emptyset\) i.e. there is nothing in the intersection
OpenStudy (anonymous):
yw
OpenStudy (anonymous):
oh okay, just to clarify, What would happen with the same problem if I multiplied p(a) and p(b)