Given the following:
p(a)= .72
p(b)=.28
p(a n B)=.14
Find each of the following.
a) the probability of A or BThis is a notation for the probability of A or B.
b) the probability of the complement of AThis is a notation for the probability of the complement of A.
c) the probability of the complement of B
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OpenStudy (anonymous):
@Loser66 please help
OpenStudy (anonymous):
similar to the last one
OpenStudy (anonymous):
@satellite73 you must be tired of helping me. thank you
OpenStudy (anonymous):
\[P(A\cup B)=P(A)+P(B)-P(A\cap B\]
OpenStudy (anonymous):
nah not at all
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OpenStudy (anonymous):
let me know what you get
OpenStudy (anonymous):
okay one sec, i'm a slow processor
OpenStudy (anonymous):
is it clear what you have to do? add \(P(A)\) to \(P(B)\) then subtract \(P(A\cap B)\) from the result
OpenStudy (anonymous):
yes I understand that
OpenStudy (anonymous):
.86?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
yay!
OpenStudy (anonymous):
second one is easier
OpenStudy (anonymous):
for that one, \(P(A^c)=1-P(A)\)
OpenStudy (anonymous):
.28
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
and the last one?
OpenStudy (anonymous):
hehe there are 3 more after the last one, would you mind helping me with them as well?
OpenStudy (anonymous):
no i don't mind at all, but first tell me what you got for the probability of B compliment
OpenStudy (anonymous):
.72 for number 3
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OpenStudy (anonymous):
ok good
OpenStudy (anonymous):
the probability of the complement of A and the complement of BThis is a notation for the probability of the complement of A and the complement of B (or neither A nor B).
OpenStudy (anonymous):
wait that would be .14 right?
OpenStudy (anonymous):
hold on you last me for a second
OpenStudy (anonymous):
the probability of the complement of A and the complement of B (or neither A nor B).
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OpenStudy (anonymous):
neither A nor B? ok
OpenStudy (anonymous):
is that right? .14
OpenStudy (anonymous):
that is the compliment of \(A\cup B\)
OpenStudy (anonymous):
so first we compute \(P(A\cup B)\) which you already did and got \(.86\)
then you subtract it from 1 and get \(.14\)
OpenStudy (anonymous):
yeah looks like you got it !
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OpenStudy (anonymous):
so do I subtract .14 from one and get .86
OpenStudy (anonymous):
wait no?
OpenStudy (anonymous):
no you did it right
you subtract \(1-.86\) and get \(.14\) that is the correct answer
OpenStudy (anonymous):
oh okay. sorry I was confused for a sec.
OpenStudy (anonymous):
the next one is p(a n b^c)
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OpenStudy (anonymous):
does that make sense?
OpenStudy (anonymous):
ok lets go to the picture
OpenStudy (anonymous):
okay!
OpenStudy (anonymous):
|dw:1373855781152:dw|
OpenStudy (anonymous):
would you tpe in words what the question is asking and I can figure it out
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OpenStudy (anonymous):
now \(A\cap B^c\) is everything that is in A and that is NOT in B
OpenStudy (anonymous):
okay would it be .58
OpenStudy (anonymous):
do you understand what i wrote there?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
yes I understand it
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OpenStudy (anonymous):
looks like you got this
OpenStudy (anonymous):
any more?
OpenStudy (anonymous):
one more! thank you so much you are a lifesaver
OpenStudy (anonymous):
no problem
OpenStudy (anonymous):
it's p(a^c n b) so I think its everything that is B and NOT a?
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
.14! thank you so much! I understand. Pictures help a lot. And if you keep seeing me on here don't be alarmed, I have like 10 assignments due by midnight. thanks for all your help
OpenStudy (anonymous):
better get busy
is it all probability?
OpenStudy (anonymous):
the next two assignments are, then it becomes functions
OpenStudy (anonymous):
nothing like waiting until the last minute...
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