Question

Question Below mate:

Answer 1

Where does the graph of
\[y = 2x^{2} + 7x + 3\]
cross the x-axis?

I know this but I forgot it, need a refresher!

Answer 2

"WILL FAN AND MEDAL!!!" xD

Answer 3

Just for that ^ I'm ignoring this :3

Answer 4

:( *sobs* ok....

Answer 5

LOL Just kidding :)

Answer 6

ahaha

Answer 7

I know ;)

Answer 8

Cross the x-axis when y = 0
So...
\[\large 0 = 2x^2 + 7x + 3\]

Answer 9

set y=0

Answer 10

Gotcha...

Answer 11

u do it

Answer 12

So which method do we use here?

Answer 13

Using whatever method feels comfortable for you :)

Answer 14

u need to get to 100 LOL

Answer 15

Factor.
0 = (2x + 1)(x + 3)

Answer 16

Ah ok factoring is better for me to understand.

Answer 17

Or you could just use the quadratic formula if you're feeling patient :D
\[\Large x = \frac{-\color{blue}b\pm \sqrt{\color{blue}b^2 - 4\color{red}a\color{green}c}}{2\color{red}a}\]

Answer 18

Yes I think I will, I got confused just now D: One sec..

Answer 19

\[\frac{ -7 \pm \sqrt7^{2} - 4 (2) (3) }{ 2(2) }\]

Answer 20

Right?

Answer 21

Oops that square root got cut off xD

Answer 22

\[\frac{ -7 \pm \sqrt{7^{2} - 4 (2) (3)} }{ 2(2) }\]

Answer 23

Simplify? :D

Answer 24

Ok so it's right, good ok so here I go:

\[\frac{ -7 \pm \sqrt{49 - 24} }{ 4 }\]

Answer 25

Yup :)
Continue... I'm watching you >:)

Answer 26

\[\frac{ -7 \pm \sqrt{25} }{ 4 }\]

*Gulps* Oh Noez.. RUNNNN :D

Answer 27

You're certainly one to take things step by step :/
\[\large \sqrt{25}=\color{red}?\]

Answer 28

\[\frac{ -7 + 5 }{ 4 }\]
\[\frac{ -7 - 5 }{ 4 }\]

Answer 29

Yes I do xD but when it's in my head I do diferently.

Answer 30

Okay... these aren't quite done yet :D

Answer 31

\[\frac{ -2 }{ 4 }\]
\[\frac{ -12 }{ 4 }\]

Answer 32

The suspense... it's killing...something :D

Finish it up, mate :)

Answer 33

\[x = -0.5\]
\[x = -3\]

Answer 34

LOL will do ;)

Answer 35

Jawohl :D

Just pointing out that these agree with the factored forms...
\[0 = (2x+1)(x + 3)\]
Implying
0 = 2x + 1
or
0 = x + 3



Would've saved you a few minutes if you'd just factored :D

Answer 36

Well I could of done the very minimal amount of quadratic equation but I like to do it thoroughly :3

Answer 37

Well, good job, anyway ^_^

Answer 38

Thanks :D btw how did you get the factored version of this, that's why I was confused :/

Answer 39

You did quite wonderfully yourself sir ;)