**HELP, MEDALS AWARDED** Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial in standard form. 4, -8, and 2 + 5i
This list isn't complete, and they do that to trick you, remember, if 2+5i is solution, what other solution do we have?
that ,means we also have 2-5i as our fourth zero that can be used to find an equation!
You got it!
you sir, are of great help!
And remember that a polynomial can be factored into (x-its zero)(x-another one of its zeros)
So I'll set it up or you and then all you gotta do is multiply (x-4)(x-(-8))(x-(2+5i)(x-(2-5i))
excellent! thanks again!
(x-4)(x+8)(x-2-5i)(x-2+5i) This is the questio that I said is a pain in the retrice cause you have to multiply all these together once, thensimpliy and add and all that ughhhh,
yea, but its something that has to be done XD
;Yep, I was about to do difference of squares ut that dont work lol the complex roots, when you multiply them you get x^2-4x+29 just to save you some time :)
jajaja just when you posted the answer i finished solving it, but that you either way!
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