In the figure below, segment RS is the altitude of the hypotenuse of triangle PQR. Which proportionality statement is true? Segment RS by QP is equal to segment QS by RS. Segment RS by QP is equal to segment PS by RS. Segment RS by QS is equal to segment PS by RS. Segment RS by QS is equal to segment QR by RS.
altitude = geometric mean of hypotenuse segments
RS^2 = QS x PS
see which of the option gives you above relation
D??
looks wrong, cuz option D doesnt even have PS in it
oh so C then?
C = \(\checkmark \)
thanks :)
yw :)
mind helping with one more please :) ??
Triangle PQR is similar to triangle ABC in the figure below What is the perimeter of triangle ABC? 10.5 inches 39.9 inches 42.0 inches 60.65 inches
perimeter is just the length around the figure
simply add all the sides of triangle ABC :)
perimeter of ABC = 14 + 17.5 +.. uhh they didnt give another side, how do we find the missing side ?
angle angle simlitary postulate is what we are dealing with?
thats right ! we use the given fact that both triangles are similar, lets setup a proportion and find the missing side
\(\large \frac{14}{4} = \frac{AC}{3}\) cross multiply and solve AC
10.5 :)
once you have AC, just add all the lengths and find perimeter
alright hold on
final answer is 42.0?
Yes !
i dont want to bother you sorry but can i just ask you if i got the right answer to this one?
The figure below shows four locations on a map. Which of the following statements is most likely correct? Location 1 is closer to Location 2 than Location 4. Location 1 is closer to Location 4 than Location 2. Location 1 is at equal distance from Location 2 and Location 4. Location 1 is at equal distance from Location 2 and Location 3.
I chose B
and you're right location 1 is closer to location 4, cuz the angle is small, its just 83. small angle eats small side
whereas the other side, the angle is 180-83 = 97. which is larger than 83 big angle eats big side
so, distance between location1 and location4 is less
yea that's what i did ;) thanks your a big help
np :) you're wlcme !
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