Question

Let g(x)=2x^2+11x. Find a solution that g(a)=40

Answer 1

well substitute x with a and f(x) with 40 so you get

\[40 = 2a^2 + 11a\]

rewrite the equation

\[2a^2 + 11a - 40 = 0\]

you need to solve the equation, it can be factored.

hope this helps.

Answer 2

g(x)=2x^2+11x
g(a)=2a^2+11a
g(a)=40
40=2a^2+11a
2a^2+11a-40=0
2a^2 + 11a - 40 = 0
2a^2+16a-5a-40=0
2a(a+8)-5(a+8)=0
(2a - 5)(a + 8) = 0
2a-5=0 or a+8=0
2a=5 or a=-8
a=5/2 or a=-8