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A sample of gas is in a cylinder of fixed volume. At 30.0 °C its internal pressure is 3200. torr. What will be its pressure at 12.0 ° C?
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from the ideal gas law: \[PV=nRT \] \[\frac{ P _{1} }{ T _{1} }=\frac{ P _{2} }{ T _{2} }\] plug in and solve
3010. torr?
not quite. what did you do?
I got 3010 torr, too.
Yea, I'm pretty sure that's the answer to the equation.
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\[\frac{ 3200 torr }{ 30 C }=\frac{ P _{2} }{ 12C } \to P _{2}=\frac{ 3200 torr }{ 30 C }*12C \to P _{2}= 1280 torr\]
@aaronq, you have to use Kelvin.....
\[\frac{ 3200 torr }{303.15 K } = \frac{ P_2 }{ 285.15 K } = \frac{3200 torr }{303.15 K } \times 285.15 K = P_2\]
haha wow. FAIR ENOUGH
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