Twice as many girls as boys were participating in a tennis tournament. Each pair of players played only one match and there were no draws. The ratio of girl winnings to boy winnings was 5:7.How many players took part in the tournament
twice as many girls as boys.....5 : 7....does that mean there is 12 games ?
I don't think so, it's the ratio of winning girls and boys.
because if there is 12 games, and 5 winning girls that means there is 10 girls, 7 winning boys means 14 boys, and 14 is not twice as 10
what do we have here lads
each pair is this doubles?
need the context haha
well...for every 12 games, girls won 5 and boys won 7.....5/7 of x...but I don't know what x is
each pair of players....so I would say it is doubles
nah i don't think it can be 12 games
would it be affected if it were mixed doubles?
just putting ideas out there
twice as many girls as boys.....2g = 1b.....I have no idea where I am going with this
loool
amistre will get it....just wait
you can just feel it
lol
awkward silence...lol
the bad net, I think so
this sentence is quite ambiguous.. Twice as many girls as boys were participating in a tennis tournament. did twice as many girls actually PLAY though, or they participated by watching the matches
b g g b b g g g g b b b g g g g g g 2:4 is 3 teams 4:8 is 6 teams 6:12 is 9 teams 2n:4n boys to girls is 3n teams to work with at best
bg bg bg bg bg gg gg gg gg gg ^ ^ ^ ^ ^ ^ 5 boys win: 5 girls win + 1 more team seems like a bad combination to me ----------------------------- bb bg bg bg gg gg gg gg gg gg ^ ^ ^ ^ ^ ^ 5 boys, 3girl + 4 girls ----------------------------- bb bb bg gg gg gg gg gg gg gg ^ ^ ^ ^ ^ ^ 5 boys, 1girl + 6 girls the setup of by girl teams doesnt seem to matter if we assume all the boys win
there is 4 players in each game...right...? so if there was 12 games, then there is 48 players... am I way off on this ?
assume 2 players in each game - singles
I thought they were doubles
thats what i thought with 48..but not 1:2
bb bb bg bg bg bg gg gg gg gg gg gg ^ ^ ^ ^ ^ ^ +6 5 boys 1girl, need 6 more girls this seems like a solution
are we sure that boys and girls are mixed
i ran thru a pairing that indicated that the bg matchup had no effect
are we sure that about this ! did twice as many girls actually PLAY though, or they participated by watching the matches!
we shouldnt try to add in extra content ...
so how many players do you think played?
i believe that 8 boys and 16 girls fits for one solution
In a game, If it is boy VS girl then, probability of boy win =1/2 and probability of girl win=1/2 If it is girl VS girl then, probability of girl win =1 If it is boy VS boy then, probability of boy win =1 Since the number of girls participating is more than the number of boys, the ratio of girl winning to boy winning can never be less than or equal to 1. So, either this question makes no sense or I didn't get the question.
"experimental" probability does not conform to "theoritical" probability.
the matches happened already, what we have is the data, we can have the ratio of winning of girls as 1 also. so...
bb bb bg bg bg bg gg gg gg gg gg gg ----> match played b b b b b g g g g g g g ---> win
then that should fit
i agree :) but im a little biased
does it matter if there is doubles playing ?
well, if 8 boys and 16 girls fits then 8n boys and 16n girls must also fit where n can be any natural number
it doesnt matter for doubles; i assumed doubles when i worked it up
because I figure if there is doubles playing, then there is 4 playersin each game
question says a pair of player plays a game
bb bb bg gg gg gg : win , 5b and 7g gg gg gg bg bg bg : lose
ohhhhh...I see
Each pair of players played only one match should we interpret it as "each player played with rest of the players once ?"
so is there 24 people ?
"each player played with rest of the players only once ?"
if so, we need to work it from scratch i would guess
does that mean there is 24 players
i would say that there is a way to solve it no matter what your approach is; just as long as you are consistent in your reasoning/interpretation of the information provided.
the answer is the 9
what you've taken is a simple case which can be worked easily - 12 matches, 24 players but if we let all combinations with all players it gets nasty
my brain hurts
if n is the number of boys then 2 n is the number of girls Let N be the total number of matches
using combinatrics we see that \[N=\left(\begin{matrix}3n \\ 2\end{matrix}\right)=\frac{ 3n(3n-1) }{ 2 }\]
N = 3n(3n-1) / 2 or N = 3n/2 ? which interpretation is correct ?
yes 1st one
\[\text{ Let} N_{ gw} \text{be the number of matches won by a girl}\]
Since the ratio between the number of matches won by girls and the number of matches won by boys is 5:7 \[\frac{ N_{gw} }{ N-N_{gw} }=\frac{ 5 }{ 7 } \text{ hence } N_{gw}=\frac{ 5 }{ 12 }N=\frac{ 5 }{ 8 }n(3n-1)\]
The number of matches played between two girls is \[\left(\begin{matrix}2n \\ n\end{matrix}\right)=\frac{ 2n(2n-1) }{ 2 }=n(2n-1)\]
Since in these matches always girls win, we have \[n(2n-1)\le \frac{5}{8}n(3n-1)\] Solving yields \[n\le 3\] Further, 8 divides \[5n(3n−1)\], therefore n= 3. Thus, there were 9 players.
do you get the solution guys ,cos i kinda get it but not fully ...can any1 expand it?
@amistre64 mention 9 tems somehow and experiment attemted the desired solution ,,,,
qoute of the day @texaschic101 "my brain hurts" lol
lol.....
without knowing how the author of the question is defining the win-lose-rematch structure ... and without having the necessary presupposed rules for such a scenario ... i wouldnt know how to verify the results of "9" people in the tournament
but theres no rematch,theres win-loose- and no draws so only win or lose
perhaps you are finding the min num of playes
9 players do not make even match ups, there will be one person waiting to play how do we determine who the 9th player competes against?
but one ammusing thing is that girls can play against girls
the num of boys should be even so should be twice of it. if you multiply it by 2, i think it is also solution of the problem.
theres some intricate win-lose-rematch structure if we are to assume a 9 member competition
and by rematch i dont mean 2 people play against each other; but rather there is a re-matching of the players
do you consider the solution above validated and reputable
everyone is playing with everyone else, so how does even or odd matter here
i cant verify the process without knowing how the matching of pairs works in the win-lose structure p1 <-> p2 p3 <-> p4 p5 <-> p6 p7 <-> p8 p9 <-> [p9?]
seems like one pair meant one player can play more than one matches, i misunderstood it.
okay so i will check how tunnis is played first,but we are not supposed to be tested on games this is a contest question not english and life skills...??? i guess this is not a good question
thanx 4 de effort
No no ... the question is okay, i seem to have presumption abt the question which was not valid. the solution seems fine.
okay so its just the logic...and understanding game structure...wich is not mentioned in the solution!!
is the 5 boys to 7 girls ratio a ratio of different people? or is the same person being counted as a gender win for multiple wins?
except the typo number of matches played between girls is 2nC2
yes i so that
thats why i typed a different solution,above
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