an object was timed as it was thrown until it returned. if the duration of the action took 2.70 secs, what is the highest point reached by the object?

Question

anonymous · Answer

8.93m

anonymous · Answer

highest point is reached when t=1.35 secs and the velocity at the highest point is zero so,
use u=v-at to find the initial velocity,
v=0
a=-9.8
t=1.35
then use s=(v^2-u^2)/2a to find the distance

jh3power · Answer

use this equation when you meet such problems.. $$t=\sqrt {\frac{2h}{g}}$$

anonymous · Answer

be careful in the above solution given by @jh3power  t is the time to reach the maximum vertical height

jh3power · Answer

it's quite useful, really...