Question

an object was timed as it was thrown until it returned. if the duration of the action took 2.70 secs, what is the highest point reached by the object?

Answer 1

8.93m

Answer 2

highest point is reached when t=1.35 secs and the velocity at the highest point is zero so,
use u=v-at to find the initial velocity,
v=0
a=-9.8
t=1.35
then use s=(v^2-u^2)/2a to find the distance

Answer 3

use this equation when you meet such problems.. \[t=\sqrt {\frac{2h}{g}}\]

Answer 4

be careful in the above solution given by @jh3power t is the time to reach the maximum vertical height

Answer 5

it's quite useful, really...