Question

Which conditional and its converse form a true biconditional?

A) If x>0, then lxl >0
B) If x=3, then x2^2=9
C) If x^2 =4, Then x=2
D) If x=19, then 2x-3=35

Answer 1

It's basically asking which pair of concepts are essentially saying the same thing...
Take choice A for instance...
Is it true that if |x| > 0, x > 0?
The answer is no, for what if x is negative?
Say, -3

|-3| = 3 > 0
But -3 is not greater than 0, so 3 > 0 is false.

So it isn't A.


Then, which is it? ;)

Answer 2

C?

Answer 3

So, you're saying, if x^2 is 4, then x = 2?

Answer 4

yes because 2x2=4

Answer 5

What about -2?

Answer 6

(-2)^2 = 4,
but -2 is not 2 :P

Answer 7

dang then its might be..... B beacuse 3x3x3= 9

Answer 8

First of all,
3x3x3 = 27, not 9 :P

Answer 9

And second, this is similar to choice c
But then again, what about -3?
(-3)^2 = 9 too, but -3 is not 3...

Answer 10

i was thinking of addition my bad :x

Answer 11

wher is the negative comming from?

Answer 12

I mean, just because x^2 = 9
doesn't mean x = 3
Because x could be -3.

Answer 13

oh then the only answer left is D

Answer 14

Yeah, that's right :P
And you just had to try every wrong answer to get it...


practice your logic next time, okay? :)

Answer 15

thanxs ill try thxs for the help