Question

(8sqrt2-8)^2

Answer 1

Like this?
\[(8\sqrt{2}-8)^{2}\]

Answer 2

Sometimes it helps to use the formula for square binomials:
\[(a-b)^2=a^2-2ab+b^2\]
Use
\[a=8\sqrt{2}\]
and b = 8 into the formula above and combine what you can.

Answer 3

I am confused... I tried to work this problem out
(8sqrt2-8) (8sqrt2-8)= 66sqrt2-64sqrt2- 64sqrt2+64

Answer 4

ok do you understand the formula above?
\[(a-b)^2=a^2-2ab+b^2\]

Answer 5

yes

Answer 6

ok can you find a^2?

Answer 7

64sqrt4

Answer 8

yes but what is sqrt 4?

Answer 9

is it 128sqrt2?

Answer 10

you're making it harder than it is. The square of a square root is just what's underneath.
\[(\sqrt{2})^2=2\]

Answer 11

its just 128. when you square a square root there will not be a root sign anymore. Square is the inverse of squareroot

Answer 12

I always make it more difficult than it needs to be. ughh

Answer 13

Does that make sense? So we have a^2 = 128 and b^2 = 64 now we need to find 2ab (the hard part to understand but not to compute)

Answer 14

its not your fault, people understand math in different ways

Answer 15

Do you see why
\[(8\sqrt{2})^2=(64)(2)\]

Answer 16

I got it now. I just needed to be walked through it. Thank you.

Answer 17

ok so what is the final answer you get?

Answer 18

192 -128sqrt2

Answer 19

omg yes it is sorry, good job lol

Answer 20

thanks ;)

Answer 21

sorry brain farted for a second ;)

Answer 22

Those are tricky but squaring square roots will help you when you start dividing these nasty things :) good luck to you