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Mathematics 8 Online
OpenStudy (anonymous):

medals rewarded! What is the probability of drawing three red cards, one at a time without replacement, from a standard deck of 52 cards?

OpenStudy (goldphenoix):

How many red cards are there in a standard deck of 52 cards?

OpenStudy (anonymous):

three

OpenStudy (goldphenoix):

Nono. How many red cards are there in TOTAL in a standard deck of 52 cards. :)

OpenStudy (anonymous):

26

OpenStudy (goldphenoix):

Good. So the probability of getting ONE red card is 1/2. Correct, or do you disagree?

OpenStudy (anonymous):

yes,but that's not an answer choice.

OpenStudy (sumi29):

Do you know how to calculate the probability of picking ONE red card from a deck? If you do, then apply that logic to calculate the probability of picking three cards, one by one, and each time the total number of cards decreases by 1, as does the total number of red cards.

OpenStudy (goldphenoix):

I know.

OpenStudy (goldphenoix):

So. The probability of finding one red card is 1/2. After you got your red card on your first try, then what is the probability of finding a red card, if you didn't replace the red card?

OpenStudy (goldphenoix):

HINT: How many red cards are there in the standard deck now?

OpenStudy (anonymous):

2/51

OpenStudy (goldphenoix):

Well. How many red cards are there in the total deck?

OpenStudy (anonymous):

26

OpenStudy (goldphenoix):

Nope. We took one red card out. So how many red cards do we have now?

OpenStudy (anonymous):

25

OpenStudy (goldphenoix):

Great! Also, the total amount of cards has decreased by 1. So how many cards are there in total now?

OpenStudy (anonymous):

51

OpenStudy (goldphenoix):

Good. So the probability of getting another red card is 25/51. Make sense so far?

OpenStudy (anonymous):

yes, but I don't see that as a choice.

OpenStudy (goldphenoix):

We're not finish. :) That was the probabiltiy of finding the second red card. Wht do you think is the probability of finding the third red card when we took out the second red card?

OpenStudy (anonymous):

24/50

OpenStudy (goldphenoix):

Good. So the probability of finding a third red card is 24/50. Now I believe you would multiply the 3 fractions. What would that give us?

OpenStudy (anonymous):

um, I got 1/22100. that can't be right

OpenStudy (goldphenoix):

Are you sure you multiply right? What did you multiply?

OpenStudy (anonymous):

everything

OpenStudy (goldphenoix):

Show ,e the fraction that you multiply.

OpenStudy (anonymous):

3/52*2/51*1/50

OpenStudy (goldphenoix):

Where did you get that fraction?

OpenStudy (goldphenoix):

Waht is the probability of getting one red card?

OpenStudy (anonymous):

1/50 I thought

OpenStudy (goldphenoix):

Nooo!! Scroll up, I corrected your mistake.

OpenStudy (anonymous):

24/50

OpenStudy (goldphenoix):

multiply by?

OpenStudy (anonymous):

26/52*25/51*24/50 and I got 2/17

OpenStudy (goldphenoix):

Are you sure? Lets simplify the fraction. You know what (24/50) simplify to?

OpenStudy (anonymous):

2/17 is correct

OpenStudy (goldphenoix):

What's the answer choices?

OpenStudy (goldphenoix):

If its around 2/17, then it is correct.

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