Determine the x intercepts, zeros, and factors for the polynomial f(x)= 3x^4+3x^3-18x^2
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
each term has a common factor of \(3x^2\) so the first step is to factor it out and write
\[f(x)=3x^2(x^2+x-6)\]
OpenStudy (anonymous):
next step is to factor \(x^2+x-6\)
do you know how to do that?
OpenStudy (anonymous):
yes?
OpenStudy (anonymous):
ok, what do you get?
OpenStudy (anonymous):
x=2?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
wait no 3
OpenStudy (anonymous):
i mean "what to you get when you factor?"
OpenStudy (anonymous):
more precisely, what do you get when you factor \(x^2+x-6\) ?
OpenStudy (anonymous):
I get the x intercepts
OpenStudy (anonymous):
right?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
or the zero's
OpenStudy (anonymous):
you get the factors that you set equal to zero to find the intercepts, yes
OpenStudy (anonymous):
but my question is "how did you factor \(x^2+x-6\) ? " what are the factors?
OpenStudy (anonymous):
positive 6 ? wait okay, I add 6 to 0 and then what do I do with the x^2
OpenStudy (anonymous):
ok lets go slow
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
you want to factor \(x^2+x-6\) so you have to think of two numbers whose product is \(-6\) and whose sum is 1
i.e. to numbers that, when you multiply them together you get \(-6\) and when you add them you get \(1)
since -6 is negative, one of them will be positive and the other will be negative
OpenStudy (anonymous):
-3 2
OpenStudy (anonymous):
those are the zeros, yes, but actually it factors as
\[x^2+x-6=(x+3)(x-2)\]
OpenStudy (anonymous):
because you switch em!
OpenStudy (anonymous):
the plus and minus
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so if \(x+3=0\) then \(x=-3\) and if \(x-2=0\) then \(x=2\)
OpenStudy (anonymous):
okay! and that's the zero"s?
OpenStudy (anonymous):
so you have three zeros
OpenStudy (anonymous):
they are \(x=2, x=-3\) and also don't forget \(x=0\)
OpenStudy (anonymous):
x=-3
x=2 and x=0
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
okay what about the x intercepts
OpenStudy (anonymous):
those are the x intercepts
OpenStudy (anonymous):
x intercept is a synonym for "zeros"
OpenStudy (anonymous):
they are the same thing??
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
are the factors of the polynomial the same thing as well?
OpenStudy (anonymous):
if \(f(2)=0\) that means \((0,2)\) is on the graph, i.e. that is where the graph crosses the \(x\) axis
OpenStudy (anonymous):
not exactly
OpenStudy (anonymous):
\[f(x)= 3x^4+3x^3-18x^2=3x^2(x+3)(x-2)\] the "factors" are
\[3x^2, x+3, x-2\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
the "zeros" are \(\{0,-3,2\}\)
OpenStudy (anonymous):
the "x intercepts" are \((0,0), (-3,0), (2,0)\)
OpenStudy (anonymous):
oh okay, I was thinking the x intercepts where something different but I understand now
OpenStudy (anonymous):
but clearly they are related
OpenStudy (anonymous):
thanks so much
Still Need Help?
Join the QuestionCove community and study together with friends!