Mathematics
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OpenStudy (anonymous):
Write the series in summation notation:
-3 + 6 - 9 + 12 - 15
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OpenStudy (anonymous):
\[\sum_{k=1}^{5} (-1)^{k}(3k)\]
OpenStudy (anonymous):
\[\sum_{k=0}^{4} (-1)^{k}-1(3k)\]
OpenStudy (amistre64):
the first one seems adequate to me
OpenStudy (amistre64):
alternating multiples of 3
OpenStudy (anonymous):
do you wanna see the other two answer choices?
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OpenStudy (amistre64):
how many correct options can you choose?
OpenStudy (anonymous):
just one
OpenStudy (amistre64):
then since the first one is adequate (i dont know how your author defines proper notation); then the others would seem a bit futile
OpenStudy (anonymous):
well the other two are quite like the first two :P
OpenStudy (amistre64):
if you want to type them up for comparison, that would be fine.
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OpenStudy (anonymous):
\[\sum_{K=0}^{4}(-1)^{k}(3k)\]
OpenStudy (anonymous):
\[\sum_{k=1}^{5} (-1)^{k} -1(3k)\]
OpenStudy (anonymous):
there :)
OpenStudy (amistre64):
is 3(4) equal to 15?
OpenStudy (anonymous):
no?
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OpenStudy (amistre64):
the last 3 simply dont match the numbers in the sequence ....
OpenStudy (anonymous):
so you plug the sequence numbers in for k?
OpenStudy (amistre64):
yes
OpenStudy (anonymous):
oh alright!! thankyou very much :)
OpenStudy (amistre64):
good luck