OpenStudy (anonymous):

How do I solve problems like this y>-2x+3 I will award medals

4 years ago
OpenStudy (amistre64):

define the boundary line shade in the side that contains "true" point solutions

4 years ago
OpenStudy (anonymous):

How would I go about finding that

4 years ago
OpenStudy (amistre64):

go about finding the shaded region? or the boundary line?

4 years ago
OpenStudy (anonymous):

Well, both.

4 years ago
OpenStudy (amistre64):

the boundary line is the equality of the given setup $(y>-2x+3)\to (y=-2x+3)$

4 years ago
OpenStudy (amistre64):

since the left side of that has no solid line underneath it; the the boundary line is not solid either

4 years ago
OpenStudy (anonymous):

So my boundary line is (-2,3)?

4 years ago
OpenStudy (amistre64):

no, you would have to graph the line: y = -2x+3 ... its not just a single point

4 years ago
OpenStudy (anonymous):

What do you mean?

4 years ago
OpenStudy (amistre64):

your boundary line is not a single point (-2,3). It is the collection of points (x,y) that satisfies the equation: y = -2x+3

4 years ago
OpenStudy (anonymous):

So how do I figure that out, I'm confused

4 years ago
OpenStudy (amistre64):

you would have gone over this material earlier on in your class. It appears that you need to review the lesson contents related to "how to graph a line".

4 years ago
OpenStudy (anonymous):

I don't get hit, that's why I'm here.

4 years ago
OpenStudy (amistre64):

the solution to the question presupposes that you already know previous lesson material. If you have no idea as to the content of the previous lessons, then you are simply not prepared for this question. You need to go back and review the content of previous lessons to have some sort of basis or foundation with which to build upon.

4 years ago
OpenStudy (anonymous):

Okay, I'll go do that. Thanks :)

4 years ago
OpenStudy (amistre64):

assuming we already know how to graph the boundary line; the solution remains to pick a point not on the line and test it out. if (0,0) is not on the line, its a good testing point. y > -2x + 3 ; test (0,0) 0 > -2(0) + 3 0 > 3 is false, so you would pick the other side of the line

4 years ago
OpenStudy (amistre64):

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4 years ago