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Mathematics 16 Online
OpenStudy (anonymous):

How do I solve problems like this y>-2x+3 I will award medals

OpenStudy (amistre64):

define the boundary line shade in the side that contains "true" point solutions

OpenStudy (anonymous):

How would I go about finding that

OpenStudy (amistre64):

go about finding the shaded region? or the boundary line?

OpenStudy (anonymous):

Well, both.

OpenStudy (amistre64):

the boundary line is the equality of the given setup \[(y>-2x+3)\to (y=-2x+3)\]

OpenStudy (amistre64):

since the left side of that has no solid line underneath it; the the boundary line is not solid either

OpenStudy (anonymous):

So my boundary line is (-2,3)?

OpenStudy (amistre64):

no, you would have to graph the line: y = -2x+3 ... its not just a single point

OpenStudy (anonymous):

What do you mean?

OpenStudy (amistre64):

your boundary line is not a single point (-2,3). It is the collection of points (x,y) that satisfies the equation: y = -2x+3

OpenStudy (anonymous):

So how do I figure that out, I'm confused

OpenStudy (amistre64):

you would have gone over this material earlier on in your class. It appears that you need to review the lesson contents related to "how to graph a line".

OpenStudy (anonymous):

I don't get hit, that's why I'm here.

OpenStudy (amistre64):

the solution to the question presupposes that you already know previous lesson material. If you have no idea as to the content of the previous lessons, then you are simply not prepared for this question. You need to go back and review the content of previous lessons to have some sort of basis or foundation with which to build upon.

OpenStudy (anonymous):

Okay, I'll go do that. Thanks :)

OpenStudy (amistre64):

assuming we already know how to graph the boundary line; the solution remains to pick a point not on the line and test it out. if (0,0) is not on the line, its a good testing point. y > -2x + 3 ; test (0,0) 0 > -2(0) + 3 0 > 3 is false, so you would pick the other side of the line

OpenStudy (amistre64):

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