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Mathematics 12 Online
OpenStudy (anonymous):

Factor completely: 2x3 + 6x2 + 2x + 6 I will award medals

OpenStudy (snuggielad):

Well, this is going to be a fun one.

OpenStudy (anonymous):

Great :)

OpenStudy (anonymous):

Hello?

OpenStudy (snuggielad):

http://www.purplemath.com/modules/factquad4.htm

OpenStudy (snuggielad):

Read that.

OpenStudy (ivettef365):

you can divide it in 2 parts as follows: (2x^3+6x^2) + (2x+6) then simplify

OpenStudy (ivettef365):

you get 2x^2(x+3)+2(x+3)

OpenStudy (ivettef365):

that is equal to (2x^2+2)(x+3)

OpenStudy (anonymous):

What happens to the GCF?

OpenStudy (anonymous):

ok, so @SnuggieLad, would this be it, 2[(x + 3)(x2 + 1)]

OpenStudy (ivettef365):

no, the GCF could be 2x^2(x+3)+2(x+3)

OpenStudy (snuggielad):

Ive you got this one.

OpenStudy (anonymous):

@ivettef365, how? Not all of the constants or coefficients have the x^2

OpenStudy (ivettef365):

that is why it needs to be divided in two parts, otherwise the GCF for the whole problem would be 2

OpenStudy (anonymous):

Which is what I thought.

OpenStudy (ivettef365):

and then you have 2(x^3+3x^2+x+3)

OpenStudy (ivettef365):

but the question asks to factor completely

OpenStudy (anonymous):

Yea, so when you factor everything don't you get 2[(x + 3)(x2 + 1)] so when you distribute you get the original problem.

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