Mathematics
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OpenStudy (anonymous):
Factor completely: 2x3 + 6x2 + 2x + 6
I will award medals
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OpenStudy (snuggielad):
Well, this is going to be a fun one.
OpenStudy (anonymous):
Great :)
OpenStudy (anonymous):
Hello?
OpenStudy (snuggielad):
Read that.
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OpenStudy (ivettef365):
you can divide it in 2 parts as follows:
(2x^3+6x^2) + (2x+6) then simplify
OpenStudy (ivettef365):
you get
2x^2(x+3)+2(x+3)
OpenStudy (ivettef365):
that is equal to
(2x^2+2)(x+3)
OpenStudy (anonymous):
What happens to the GCF?
OpenStudy (anonymous):
ok, so @SnuggieLad, would this be it, 2[(x + 3)(x2 + 1)]
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OpenStudy (ivettef365):
no, the GCF could be
2x^2(x+3)+2(x+3)
OpenStudy (snuggielad):
Ive you got this one.
OpenStudy (anonymous):
@ivettef365, how? Not all of the constants or coefficients have the x^2
OpenStudy (ivettef365):
that is why it needs to be divided in two parts, otherwise the GCF for the whole problem would be 2
OpenStudy (anonymous):
Which is what I thought.
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OpenStudy (ivettef365):
and then you have
2(x^3+3x^2+x+3)
OpenStudy (ivettef365):
but the question asks to factor completely
OpenStudy (anonymous):
Yea, so when you factor everything don't you get 2[(x + 3)(x2 + 1)] so when you distribute you get the original problem.