A line passes through the point (0, 2) and has a slope of -1/4 What is the equation of the line?
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OpenStudy (anonymous):
The equation you'll be using is:
\[y-y_1=m(x-x_1)\]Here, m is the slope of the line, and x_1,y_1 are the x and y coordinates of any point on the line. You have the slope and a point, so you can just plug in and simplify as needed.
OpenStudy (anonymous):
so, how should it look like?
OpenStudy (anonymous):
?
OpenStudy (jdoe0001):
point-slope form -> \(\huge y-y_1=m(x-x_1)\)
m = slope
(0, 2) = \(\bf (x_1, y_1)\)
OpenStudy (jdoe0001):
plug your values in, solve for "y" to get your equation
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OpenStudy (anonymous):
so how will that look
OpenStudy (jdoe0001):
well, plug in the values, and you'd know
OpenStudy (anonymous):
give me a sec
OpenStudy (anonymous):
yeah im lost
OpenStudy (jdoe0001):
well, did you plug in the values?
the point-slope form takes, slope, and "x" and "y" coordinates for a point given
you're given all 3 of those
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