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OpenStudy (anonymous):
What is the 43rd term of an arithmetic sequence with a rate of increase of -6 and a11 = 12?
A. -174
B. -176
C. -180
D.-186
E. -240
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hartnn (hartnn):
so, d=-6
a11= 12
firstly,use the formula \(\large a_n=a_1+(n-1)d\)
to get the value of a1 (n = 11)
OpenStudy (anonymous):
A little confused still
hartnn (hartnn):
\(a_n=a_1+(n-1)d\)
is the general formula
we are given, a11 =12 ....so,n=11
d=-6
just plug these in and find the value of a1
OpenStudy (amistre64):
just let a11 = a1
a(11-10) = a1
a(43-10) = a33
OpenStudy (anonymous):
Isn't the answer -174?
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OpenStudy (amistre64):
or in this case it might be even simpler to go to a0
an = 12 - 6n;
a(43-11) = a32 = 12 -6(32)
OpenStudy (anonymous):
The answeris A?
OpenStudy (amistre64):
of course not ...
OpenStudy (amistre64):
12 - 6(32)
hartnn (hartnn):
how did u get -174 ?
its actually 42nd term...
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OpenStudy (anonymous):
180! Yes? And i'm in summer school. And my math teacher isnt here, so when my science teacher helped me I guess he was wrong..
OpenStudy (amistre64):
logically: 43 - 11 = 32 so you are 32 interation away.
32(-6) must be added to 12
hartnn (hartnn):
-180 yes, but more important is that you know exactly how to get it...
OpenStudy (amistre64):
*iterations ... my fingers hate me
OpenStudy (anonymous):
Thank you both.
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hartnn (hartnn):
welcome ^_^
OpenStudy (amistre64):
good luck ;)
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