Question

help pls

Answer 1

We're given with the value of y in the terms of x already, so can you tell me the method in which we substitute the value of a variable in another equation? That method is your answer.

And, Welcome to OpenStudy @xbob2

Answer 2

i tried but came up clueless
and i have a new acount because my old one got deleted

Answer 3

I have solution for the given question as :

\(\bf{\mathsf{y = \cfrac{1}{2} x \quad \text{(Given)} ...... (1) \\
2x + 3y = 28 \quad \text{(Given)} ..... (2)\\
\text{Putting the value of y from equation (1) into equation (2)} \\
2x + 3(\cfrac{1}{2}x) = 28 \\
2x + \cfrac{3}{2} x = 28 \\
\cfrac{4x + 3x }{2} = 28\\
\cfrac{7x}{2} = 28\\
7x = 56 \\
\boxed{x = 8}}}\)

Can you tell me, which method I have used here?

Answer 4

does y equal 4?

Answer 5

Yes, but can you tell me , which method is used here?

Answer 6

That is exactly the method I would use

Answer 7

id say distributive but im probably wrong

Answer 8

No, it's not distributive. What do you think about elimination ?

Answer 9

xbob...what does y =

Answer 10

Do you know what is substitution and elimination?

Answer 11

@xbob2 , Check out this link :

http://www.mathsisfun.com/algebra/substitution.html

Answer 12

that was my next guess

Answer 13

y = 1/2x and mathsolver subbed 1/2x in for y in the 2nd equation

Answer 14

You probably, have not got the concepts right yet. Please go through the following lesson :

http://www.mathsisfun.com/algebra/systems-linear-equations.html

Answer 15

good job mathsolver :)

Answer 16

i remember you from yesterday texaschic101 my name is xbob

Answer 17

I remember you too :)

Answer 18

Thaks @texaschic101 .

Answer 19

*Thanks

Answer 20

just telling the truth

Answer 21

id say elimination

Answer 22

Isn't that the same problem ?

Answer 23

no

Answer 24

I am seeing the same problem

Answer 25

Just write the problem and I will give you my opinion