y=(5x^2-1)^8(1-6x^3) can u help me using general formula

Question

anonymous · Answer

general formula for what?  you certainly do not want to multiply all this mess out!

anonymous · Answer

n.u^n-1 time DU/DX ... finding Y

anonymous · Answer

oooh you want the derivative right?

anonymous · Answer

yes.

anonymous · Answer

but can we use the derivative of quotient?

anonymous · Answer

$$y=(5x^2-1)^8(1-6x^3) $$
use 
$$(fg)'=f'g+g'f$$ with 
$$f(x)=(5x^2-1)^8,f'(x)=8(5x^2-1)^7\times 10x\
g(x)=1-6x^3,g'(x)=-18x^2$$

anonymous · Answer

yesss .... then what next?

anonymous · Answer

that is it

anonymous · Answer

plug them in to the formula

anonymous · Answer

after pulging them ... what next?

anonymous · Answer

have a snack?

anonymous · Answer

$$(fg)'=f'g+g'f$$
$$80x(5x^2-1)^7(1-6x^3)-18x^2(5x^2-1)^8$$

anonymous · Answer

i can't imagine trying to simplify this mess in any way, although both terms have a common factor of $(5x^2-1)^7$ which you could factor out if you like

anonymous · Answer

too much algebra for not enough payback
i would leave it as it is