Question

y=(5x^2-1)^8(1-6x^3) can u help me using general formula

Answer 1

general formula for what? you certainly do not want to multiply all this mess out!

Answer 2

n.u^n-1 time DU/DX ... finding Y

Answer 3

oooh you want the derivative right?

Answer 4

yes.

Answer 5

but can we use the derivative of quotient?

Answer 6

\[y=(5x^2-1)^8(1-6x^3) \]
use
\[(fg)'=f'g+g'f\] with
\[f(x)=(5x^2-1)^8,f'(x)=8(5x^2-1)^7\times 10x\\
g(x)=1-6x^3,g'(x)=-18x^2\]

Answer 7

yesss .... then what next?

Answer 8

that is it

Answer 9

plug them in to the formula

Answer 10

after pulging them ... what next?

Answer 11

have a snack?

Answer 12

\[(fg)'=f'g+g'f\]
\[80x(5x^2-1)^7(1-6x^3)-18x^2(5x^2-1)^8\]

Answer 13

i can't imagine trying to simplify this mess in any way, although both terms have a common factor of \((5x^2-1)^7\) which you could factor out if you like

Answer 14

too much algebra for not enough payback
i would leave it as it is