Question

A waiter is carrying a tray above his head and walking at a constant velocity. If he applies a force of 5.0 newtons on the tray and covers a distance of 10.0 meters, how much is the work being done?

Answer 1

\(W=F*s*cos\theta\)
where \(W\)=work done
\(F\)=force
\(s\)=distance
and \(theta\)= the angle between \(F\) and \(s\)