Confirm that f and g are inverses by showing that f(g(x)) = x and g(f(x)) = x. f(x) = x - 7 / x + 2 and g(x) = -2x-7 / x-1
Please help :) I forgot how to do this but you should have covered it already.
yes i did :) hold on
Oh yay you're typing i'm still here
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its gonn start like tht
I did get that far. My big question is after this step and how to take it. Do I flip the denominator and multiply both terms?
\[f(x) =\frac{ x - 7 }{ x + 2}\] \[g(x)=\frac{-2x-7}{x-1}\]
what @kiimiilee wrote is correct here is the first step :
\[f(g(x))=f(\frac{-2x-7}{x-1})=\frac{ \frac{-2x-7}{x-1}- 7 }{ \frac{-2x-7}{x-1} + 2}\]
Does x=-7/2?
from there on in it is a bunch of annoying algebra, which will lead to a whole raft of cancellation, and you should end up only with \(x\) at the end
no, \(x\) is not a number at all your job is to compose the function and find that you end up with the identity, i.e. that \[f(g(x))=x\]
So if I demonstrate that both f(g(x)) and g(f(x)) = -7/2 would I be answering the questioN?
yes but it would be wrong
Ok then where would I go from there.
you simplify i think @satellite73
multiply top and bottom by x-1
OK then what?
you keep canceling and you'll get x
ok ty
np :)
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