Question

The equation of a circle is (x - 3)2 + (y + 2)2 = 25. The point (8, -2) is on the circle.

What is the equation of the line that is tangent to the circle at (8, -2)?

Answer 1

did you take the derivative?

Answer 2

or is this more about slopes and algebra?

Answer 3

geometry

Answer 4

algebra-wise, we need to find the center of the circle

(x - 3)2 + (y + 2)2
^ ^

(3,-2) is the center of the circle; right?

Answer 5

mhmm.

Answer 6

so the slope between the center point and the stated point is?

Answer 7

the option for answers are
y= 8
x= 8
x= 3
y= 3

Answer 8

slope of 0?

Answer 9

yes, the slope is zero, the perpendicular slope is ... well, we get a vertical line

Answer 10

how do we define a vertical line thru (8,-2)?

Answer 11

x=8?

Answer 12

correct

Answer 13

Thank you!

Answer 14

youre welcome