Question

Indicate the equation of the given line in standard form.

The line that is the perpendicular bisector of the segment whose endpoints are R(-1, 6) and S(5, 5)

Answer 1

m = y2-y1/x2-x1
= (5-6)/(5+1)
= -1/6
therefore m of the perpendicular = 6 as m x m(perp) = -1
mid point = (x1+x2)/2, (y1+y2)/2
= 4/2, 11/2
= 2, 11/2
subst in y = mx + c
11/2 = 6(2) + c
c= -13/2
therefore y = 6x - 13/2
or 2y = 12x - 13

Answer 2

what is it in standard form

Answer 3

According to www.mathsisfun.com/algebra/standard-form.html, the standard form for a linear equation is Ax + By = C. So here it would be 12x - 2y = 13.

Answer 4

goood looking thanks

Answer 5

You're welcome! ;)