Question

I earlierly have posted this question, but bymistake I closed it... So please let me allow to get the answer again




The depth d(x), in feet, of a circular swimming pool at a point x feet from the edge is represented by the function below.

The function d of x equals 1 plus one-eighth x]

If the depth varies from 1 foot to 4 feet, which inequality describes the domain of the function?

0 ≤ x ≤ 8

0 ≤ x ≤ 24

0 ≤ x ≤ 40

1 ≤ x ≤ 8

Answer 1

\( d(x) = 1 + \dfrac{1}{8} x \)

When \(d(x) = 1\),

\( 1 = 1 + \dfrac{1}{8} x \)

\(0 = \dfrac{1}{8} x \)

\(0 = x\)

When \(d(x) = 4\),

\( 4 = 1 + \dfrac{1}{8} x \)

\(3 = \dfrac{1}{8} x \)

\(24 = x\)

For d(x) to be between 1 and 4, x is between 0 and 24, and that is domain.

Answer 2

What's the correct option then ?

Answer 3

@mathstudent55

Answer 4

I wrote above:
"x is between 0 and 24, and that is domain."

Don't you see an option with 0 and 24 in it?

Answer 5

http://openstudy.com/study#/updates/51e5892ae4b04edf24848d09