Question

Find the value of $1,300 invested at 4.2% interest compounded continuously for 5 years, 9 months. Round your final answer to the nearest hundredth, or cent. Show your work. Use e= 2.718.

Answer 1

so far I have 1300* e^(0.042)(3/4)

Answer 2

im just wondering if that equation is correct

Answer 3

because 3/4 of an yr. is 9 mos.

Answer 4

hello?

Answer 5

hello :) correct, also dont forget to include 5 years

Answer 6

5 years 9 months

5 years + 9 months

5 years + 3/4 year

5 + 3/4 year

23/4 years

Answer 7

yea sorry that's what I meant :)

Answer 8

i got $1655.10 for an answer?

Answer 9

looks correct, good work :)

Answer 10

ok & what abt this one?

Answer 11

Use the Properties of Logarithms to solve the equation for x. Round your answer to the nearest hundredth. Show your work.

e^(5x)+2=6

Answer 12

\(\large e^{(5x)} +2=6\)

Answer 13

yea

Answer 14

subtract 2 first?

Answer 15

thats good move :) keep going

Answer 16

e^(5x)=4

Answer 17

then u do.. log(4) divided by

Answer 18

yes, take ln both sides

Answer 19

ln(4)/ln(e^5
)

Answer 20

\(\large e^{(5x)}=4 \)

take ln both sides

\(\large \ln e^{(5x)}= \ln 4 \)

\(\large 5x \ln e= \ln 4 \)

\(\large 5x = \ln 4 \)

\(\large x = \frac{\ln 4}{5}\)

Answer 21

plugit in your calculator

Answer 22

what you got is also correct :) good work !!

Answer 23

i gotta run, cya

Answer 24

i got .278

Answer 25

ok bye, thanks

Answer 26

i got .277

Answer 27

rounding to the nearest hundreth it wud be :-
.28

Answer 28

yup. thanks :)