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OpenStudy (anonymous):
\[\sqrt{98^5}\]
OpenStudy (anonymous):
Need to learn the steps properly :P
OpenStudy (uri):
Step 1:Logout
Step 2:Go to a stationery
Step 3:Buy a scientific calculator.
OpenStudy (anonymous):
...
OpenStudy (anonymous):
*goes to laptop scientific calculator*
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OpenStudy (anonymous):
The choices are like: \[2x^2 \sqrt{7x}\]
OpenStudy (anonymous):
-.- Help me please.
OpenStudy (luigi0210):
\[\sqrt{(2*49)^5}\]
OpenStudy (anonymous):
What would I do next? I don't understand .-.
OpenStudy (anonymous):
why dont you first rewrite it like this \[\sqrt{98^4*98}\]
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OpenStudy (anonymous):
Then what would I do? I don't see what the next step would be to do.
OpenStudy (anonymous):
what would happen if we put out the 98^4
OpenStudy (luigi0210):
Oh i see. Think of it this way:
\[98^{4/2}*\sqrt{49*2}\]
OpenStudy (anonymous):
Divisible by 2?
OpenStudy (anonymous):
so yeah you would actually get \[98^2*\sqrt{98}\]
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OpenStudy (luigi0210):
Or simplified down more would be:
\[7*98^2 \sqrt{2}\]
OpenStudy (anonymous):
How do you get it to 2?
OpenStudy (luigi0210):
Breaking it down.
OpenStudy (anonymous):
Dividing 98 by 49?
OpenStudy (anonymous):
yeah you can rewrite 98 as 49*2
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OpenStudy (luigi0210):
Yup, yup
OpenStudy (anonymous):
Oh okay. Well I have a few more questions could one of you help? They look easier than this one xD
OpenStudy (luigi0210):
And the perfect square of 49 is 7
OpenStudy (anonymous):
Oh that's how you got 7
OpenStudy (luigi0210):
Yup :D
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OpenStudy (anonymous):
Makes more sense now :P
OpenStudy (anonymous):
a lot more sense xDD
OpenStudy (anonymous):
With the information I was given the answer is: \[7x^2 \sqrt{2}\] correct?
OpenStudy (anonymous):
I wrote the first thing wrong. \[\sqrt{98x^5}\]
OpenStudy (anonymous):
you need that to be simplified?
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OpenStudy (luigi0210):
Yea thats right
OpenStudy (luigi0210):
But you're missing a piece
OpenStudy (anonymous):
Which is?o;
OpenStudy (luigi0210):
\[\sqrt{49*2*x^4*x}\]
OpenStudy (anonymous):
So it's \[7x^2\sqrt{2x}\]
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OpenStudy (luigi0210):
There you go :)
OpenStudy (anonymous):
Can you help me with a few more?o;
OpenStudy (anonymous):
\[\sqrt{48}\] is my next one.
OpenStudy (luigi0210):
Well try them first then post a new question if you need help
OpenStudy (anonymous):
Alrighty. (:
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OpenStudy (luigi0210):
\[\sqrt48=\sqrt{4*4*3}\]
OpenStudy (anonymous):
I don't know how to do them at all, that's why I asked for steps to learn :P
OpenStudy (anonymous):
\[4 \sqrt{3}\] is that equal to \[\sqrt{4*4*3}\]
OpenStudy (luigi0210):
Yea :)
OpenStudy (anonymous):
Can you explain why? :P
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OpenStudy (luigi0210):
I'm awful at explanations.. sorry brah D:
OpenStudy (anonymous):
How do you know it's equal to eachother then? :P
OpenStudy (anonymous):
because \[\sqrt{4*4*3}=\sqrt{4^2*3}\] so since its 4^2 when we pull it out of the squareroot we look for \[\sqrt{4^2}=4\] so we have \[4*\sqrt{3}\] left
OpenStudy (anonymous):
Understandable :P
OpenStudy (anonymous):
Let me get your opinion. on this.
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OpenStudy (anonymous):
\[\sqrt{100}\] would be equal to \[50\sqrt{2}\] ?
OpenStudy (anonymous):
not necessarily :p
OpenStudy (anonymous):
absolutely not xD
OpenStudy (anonymous):
Dang.-.
OpenStudy (anonymous):
Ok so u'd find the factors of 100 which are: 10 * 10. Since it's got 2 of the same factor u can take it out of the square root|dw:1374014739333:dw|