i need your help in solving this problem 2x^2 +7x +6=0 what is the minimum and maximum this problems is new to me

Question

anonymous · Answer

This parabola is concave up, which means it opens upward. We know this because the coefficient of the x^2 term is positive. So, since it opens upward, it must have a minimum, but no maximum. As for how to find the minimum, that really depends on your level in math. In calculus, we would take the derivative equal to 0. If you're in algebra or a similar level class you've probably learned that the vertex is located at 
$$x=-b/(2a)$$where a is the coefficient of the x^2 term and b is the coefficient of the x term.

anonymous · Answer

yes you are correct i am in algebra and we are learning about vertex

anonymous · Answer

Okay, so for any quadratic you can find the x coordinate of the vertex by the expression (-b)/(2a). So in this case our b value is 7 and our a value is 2, so plug those in to find the x coordinate.

anonymous · Answer

that is the problem i am having I do not know how to work the problem

anonymous · Answer

Ok. Simply plug in the a and b values into this equation:
(-b)/(2a). In our equation, a=2 and b=7

anonymous · Answer

so you will have x = -b/a?