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determine the value of a so that the average rate of change of the function j(x)= 3x²+ax-4 over the interval -1≤x≤2 is 8
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average rate of change, as in \(\frac{f(2)-f(-1)}{3}=8\) ?
we can do this for sure
you want \[\frac{f(2)-f(-1)}{3}=8\] or \[f(2)-f(-1)=24\] so lets compute the left hand side okay?
\[f(2)=12+2a-4=2a+8\] and \[f(-1)=3-a-4=-a-1\] you with me so far?
yep
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so you want \[2a+8-(-a-1)=24\] i.e. \[3a+9=24\]
oh! and then solve for a
yeah should take only two steps right?
3a=24-9 3a=15 a=5
YAY! awesome thanks ! :)
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that ought to do it, yes
yw
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