Please Help! Will give medal and become fan Write the equation of the line that is parallel to the line y = 2x + 2 and passes through the point (5, 3). y=2x - 17 y= -1/2x - 2 y=2x - 2 y=-1/2x - 7
The equation you'll want to use here is: \[y-y_1 = m(x-x_1)\]Where m is the slope, x_1 and y_1 are the coordinates of any point on the line. Since the line is parallel to y=2x+2, it must have the same slope, so m=2. Now, just plug in the slope and your point (5,3) and simplify.
So it will be the second one?
Parallel lines have the same slope. The line you have is in the slope-intercept form, \(y = mx + b \) where \(m = \) slope, and \(b = \) y-intercept
No, the second one has a slope of -1/2 and not 2.
Then the first one because it has the slope of 2
Now look at your line: \(y = 2x + 2\) When you compare it with \(y = mx + b\), you see that the slope m = 2. Since parallel lines have the same slope, the line you are looking for also has a slope of 2. That means the line you need has the equation: \(y = 2x + b\) Now we need to find b. Since you have a given point, \((5, 3)\), insert the x- and y-coordinates of the point into \(y = 2x + b\) and solve for b: \(y = 2x + b\) \(3 = 2(5) + b\) \(3 = 10 + b\) \( -7 = b\) Now that you know that \(b = -7\), insert that value in the equation \(y = 2x + b\) getting: \(y = 2x - 7\)
so that wouldnt be it?
Perhaps the original poster has a typo. I think choice A shoud read \(y = 2x - 7\), not \(y = 2x - 17\).
Thank you so much
You're welcome.
Can you do another problem please
Yes. Please start a new post.
ok
Join our real-time social learning platform and learn together with your friends!