Mikalee, a fighter pilot, ejects from her burning plane. Once she is safely on the ground, she launches a flare to attract the attention of a rescue plane. The initial velocity of the flare is 1600 ft/sec. What is the maximum height of the flare? 50 ft 400 ft 4,000 ft 40,000 ft
We can use the following equation from kinematics: \[v_f ^2 = v_i ^2 + 2ad\]Where v_f and v_i are the final and initial velocities, a is acceleration due to gravity, and d is the distance. We're solving for the distance. When the flare is at its max height, its velocity is zero. So: \[0=(1600 ft/s)^2 + 2(-32 f/s^2)d\]Now, solve for d. Can you try solving this on your own?
is there a more simple equation?
I believe this is as simple as you're going to get.
ok, can you take me step by step ?
Sure. We'll square the 1600 ft/s and multiply the 2 with the -32 ft/s^2 to get: \[0=2560000 ft^2 / s^2 - (64 ft/s^2)d\]Now add 64d to both sides: \[d(64 ft/s^2)=2560000 ft^2 / s^2\]Can you do the last step?
the answer is 40000?
Yes, exactly.
so if you were trying to find the maximum height of the flare would you ........
The most direct method is to use the kinematics formula I gave you above.
Join our real-time social learning platform and learn together with your friends!