MEDAL AND FAN! (:
A set of data with a mean of 45 and a standard deviation of 8.3 is normally distributed. Find the value that is –2 standard deviations away from the mean.
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jimthompson5910 (jim_thompson5910):
z = (x - mu)/sigma
-2 = (x - 45)/8.3
solve for x
OpenStudy (emilyjones284):
What would be the first step to solving for x?
jimthompson5910 (jim_thompson5910):
multiplying both sides by 8.3
jimthompson5910 (jim_thompson5910):
-2 = (x - 45)/8.3
-2*8.3 = x - 45
-16.6 = x - 45
OpenStudy (emilyjones284):
so then its -16.6(x-45)?
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jimthompson5910 (jim_thompson5910):
close, look at what I wrote above
OpenStudy (emilyjones284):
Ohhhhhh okay so its 28.4?
OpenStudy (emilyjones284):
wait thats not an option for an answer
jimthompson5910 (jim_thompson5910):
what are your options?
OpenStudy (emilyjones284):
20.1, 78.9, 69.9, 48.0
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jimthompson5910 (jim_thompson5910):
hmm I'm getting 28.4 as well, so not sure why it's not showing up
OpenStudy (emilyjones284):
did we do it wrong?
jimthompson5910 (jim_thompson5910):
double check all the numbers to make sure they are correct (like the 45 or 8.3 or -2)
jimthompson5910 (jim_thompson5910):
no we did it correctly
OpenStudy (emilyjones284):
Oh wow I'm sorry instead of -2 it is +3, I dont know how I did that
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jimthompson5910 (jim_thompson5910):
that's ok, glad you checked
jimthompson5910 (jim_thompson5910):
so you need to solve
3 = (x - 45)/8.3
OpenStudy (emilyjones284):
Okay I got 69.9 (:
jimthompson5910 (jim_thompson5910):
me too
OpenStudy (emilyjones284):
Thanks (:
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