with the restriction x does not = 2 what is the simplified form of (2x-7/x-2) - (x-5/x-2)
\[\frac{a}{b}-\frac{c}{b}=\frac{a-c}{b}\] make sure to use parentheses, so the first step is to write \[\frac{2x-7-(x-5)}{x-2}\] then you can clean up the numerator by removing parentheses and combining like terms
i did that and it gave me x-2/x-2 which is one but that is incorrect
for your problem you get =1 (x≠2)
i got 1 for the simplified answer, but its incorrect, and I don't know why. 2x−7−(x−5) = x - 2 is what i got and x-2/x-2=1
what makes you think 1 is wrong ? (strictly speaking the answer is 1 for x≠2) are you sure you typed in the correct question ?
yes, im sure. I submitted one already, and it was incorrect...
hmm i am going to stick with that answer
(2x-7/x-2) - (x-5/x-2) I assume this is a sloppy version of (2x-7)/(x-2) - (x-5)/(x-2) = 1 for x≠2 however, if we interpret using order of operations 2x - 7/x -2 - (x -5/x -2) which is different. If you are sure the question is (2x-7)/(x-2) - (x-5)/(x-2) then ask your teacher, because the answer is 1, x≠2 see http://www.wolframalpha.com/input/?i=%282x-7%29%2F%28x-2%29+-+%28x-5%29%2F%28x-2%29
this \[\frac{2x-7}{x-2}-\frac{x-5}{x-2}\] is the correct question right?
it could be an error in the program, ill try it again though...and yes those are the right questions.
ok
hmm...idk, ill ask my teacher. thanks for the help though!
she says that's correct! thank you both so much!
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