Jose needs to enclose a rectangular section of his yard. The perimeter of the section is 27 feet, and the area is 35 square feet. Find the length and width of the section.
Part I: Let L = length of the section and let W = width of the section. Write an equation for the perimeter of the section. Hint: P = 2(L+W).
Part II: Use the equation you wrote in Step 1 and solve for W. Show your work.
Part III: Using L and W as defined in Step 1, write an equation for the area of the section. Hint: A = LW.
Part IV: Substitute the expression you found for W in Part 2 into the area equation in Part 3.

Question

Jose needs to enclose a rectangular section of his yard. The perimeter of the section is 27 feet, and the area is 35 square feet. Find the length and width of the section. 
Part I: Let L = length of the section and let W = width of the section. Write an equation for the perimeter of the section. Hint: P = 2(L+W).
Part II: Use the equation you wrote in Step 1 and solve for W. Show your work.
Part III: Using L and W as defined in Step 1, write an equation for the area of the section. Hint: A = LW.
Part IV: Substitute the expression you found for W in Part 2 into the area equation in Part 3.

lncognlto · Answer

Okay, do you know how to begin?

anonymous · Answer

not really

lncognlto · Answer

Right, p = 2(l + w), as given.
so 27 = 2(l+w).
Now isolate w.

anonymous · Answer

how would i do that?

lncognlto · Answer

Just get it on its own: 27/2 = l + w
so w = ?

anonymous · Answer

13.5?

lncognlto · Answer

13.5 - l, exactly. Then A = LW
so 35 = lw

anonymous · Answer

thats just the area 35

lncognlto · Answer

Yes, now substituting w = 13.5 - 1 into lw = 35 gives l(13.5-l) = 35
sorry, I got lost.

lncognlto · Answer

Sorry, I can't make this work. You can repost the question to get some proper help :)

anonymous · Answer

okay