Question

help?



Which of the following is the solution of log x - 50.001 = -3 ?
x = 5
x = 7
x = 13
x = 15

Answer 1

it is \(\log_x(50.001)=-3\) ???

Answer 2

something goofy about this problem

Answer 3

If that is the problem, I believe all the choices are wrong

Answer 4

no sorry the five is with the x

Answer 5

lets try
\[\log_{5x}(.001)=-3\] maybe ?

Answer 6

its log x-5 together then 0.001=-3

Answer 7

once more with feeling
\[\log_{x-5}(.001)=-3\]

Answer 8

yes!

Answer 9

kk so since \(10^{-3}=0.001\) you have \(x-5=10\) and you can solve for \(x\) in one easy step

Answer 10

can you show me how? I really don't know how to do these..

Answer 11

this is a tricky one because there is no real algebra of even log way to solve it
you have
\[\log_{x-5}(0.001)=-3\] which is the same as writing in exponential form
\[(x-5)^{-3}=0.001\]

Answer 12

at this point you just sort of have to know that since
\(10^{-3}=\frac{1}{10^3}=\frac{1}{1000}=0.001\)
that this means \(x-5\) must be equal to \(10\)

Answer 13

in other words you were really just supposed to "know" it, you can't really "solve" for it
in any case if \(x-5=10\) then \(x=15\)

Answer 14

thank you so much!

Answer 15

yw