In a manufacturing plant, there is a 10% chance that a stamp will be placed on a box upside down. The plant shipped 37 boxes today. What is the probability that 7 of the boxes have an upside-down stamp?
use the binomial for this one
7 upside down and 30 not upsides down, probability would be \[P(x=7)=\binom{37}{7}(0.1)^7(0.9)^{30}\] and a calcualator
\[\left(\begin{matrix}x \\ y\end{matrix}\right) = \frac{ x! }{ (y!)[(x - y)!] }\]where x! = (x)(x-1)(x-2) . . . (3)(2)(1) \[\left(\begin{matrix}x \\ y\end{matrix}\right)\]is the number of ways you can select "y" elements from "x" objects. In this case, it is the number of ways you can select 7 boxes from the whole group of 37.\[\left(\begin{matrix}37 \\ 7\end{matrix}\right) = \frac{ (37)(36)(35) . . . (3)(2)(1) }{ [(7)(6)(5)(4)(3)(2)(1)][(30)(29)(28)...(3)(2)(1)] }\]
That will come down to (more easily):\[\left(\begin{matrix}37 \\ 7\end{matrix}\right) = \frac{ (37)(36)(35)(34)(33)(32)(31) }{ (7)(6)(5)(4)(3)(2)(1) }\]
so do i multiply 37 x 36 x 35?
Some calculators have probability and stats functions and buttons, and you can use those if you have them. If you have only a very basic calculator at hand, you can multiply it out, but it's not too hard, because it's only 7 numbers in the numerator and 7 in the denominator. Your Windows operating system (if you are running Windows) has a scientific calculator that is super-easy to use.
No, my second post has 7 numbers in the numerator and 7 in the denominator. Then you have to finish up with the two factors that are to the 7th and 30th powers.
So, hopefully,\[\left(\begin{matrix}37 \\ 7\end{matrix}\right)\]which was the hard part is no problem for you now? @wequess2 ?
One other thing, and I see now why you asked a certain question above, the ellipses: 3 dots -> . . . means a continuation, either into infinity (if nothing after the dots) or a termination at what comes after (with everything in between, "in pattern").
For example: 1 + 2 + 3 + . . . + 8 + 9 + 10 means: 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10
np. Look at my second post above for:\[\left(\begin{matrix}37 \\ 7\end{matrix}\right)\]On the right-hand side, it has 7 factors in the numerator and the denominator. That is self-explanatory. Multiply that out and get the fraction. You'll have to use a calculator. Once you have that, you multiply this by: \[(0.1)^{7}(0.9)^{30}\]and you are completely done.
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