How to find sin 60 degrees in simplest radical form???
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OpenStudy (jdoe0001):
hmm, use your Unit Circle :)
OpenStudy (jdoe0001):
I'd think it'd have it already in a simplified radical form
OpenStudy (anonymous):
OpenStudy (anonymous):
All I was taught to do sine, cosine, and tangent with is an online calculator, so when I do sin 60 I get 0.866025403784439 but I have absolutely no idea how to make it a radical...
OpenStudy (jdoe0001):
ok, let's use the pythagorean theorem then, usually in a 60 degrees right-angle
you'd have this kind of relation
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OpenStudy (anonymous):
how do you use Pythagorean theorem though if you don't have the side lengths?
OpenStudy (jdoe0001):
|dw:1374092488215:dw|
so for the Unit Circle that'd be |dw:1374092551845:dw|
now let's find what the other side is, that is the hypotenuse,
because cosine = opposite/hypotenuse
OpenStudy (anonymous):
square root of 5?
OpenStudy (jdoe0001):
no ....
OpenStudy (jdoe0001):
lemme change that for the unit circle, the "Unit" circle can't be more than 1, hold on
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