Find the m angle T
answers:
40.5°
38.5°
139.5°
124.5°
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OpenStudy (anonymous):
OpenStudy (anonymous):
your using the law of cosine right?
jimthompson5910 (jim_thompson5910):
you are correct
jimthompson5910 (jim_thompson5910):
so what do you get when you do?
OpenStudy (anonymous):
gotta work it out
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jimthompson5910 (jim_thompson5910):
alright
OpenStudy (anonymous):
I don't know how I would put it
OpenStudy (anonymous):
t^2 = s^2 + r ^2 ?
jimthompson5910 (jim_thompson5910):
the law of cosines is
c^2 = a^2 + b^2 - 2*a*b*cos(C)
so in this case, we would say
t^2 = r^2 + s^2 - 2*r*s*cos(T)
jimthompson5910 (jim_thompson5910):
then plug everything in to get
t^2 = r^2 + s^2 - 2*r*s*cos(T)
16^2 = 24^2 + 22^2 - 2*24*22*cos(T)
from here, you solve for T
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
so I don't do anything with the cos (T) ?
jimthompson5910 (jim_thompson5910):
think of it as its own variable
you solve for cos(T) first, then you further solve for T once you have isolated it
jimthompson5910 (jim_thompson5910):
so if you really want to, you can replace cos(T) with x
that would mean
16^2 = 24^2 + 22^2 - 2*24*22*cos(T)
turns into
16^2 = 24^2 + 22^2 - 2*24*22*x
jimthompson5910 (jim_thompson5910):
then you would solve 16^2 = 24^2 + 22^2 - 2*24*22*x for x like normal
after you have isolated x, you replace x with cos(T)
finally, you would solve for T using the arccosine function
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OpenStudy (anonymous):
this is what I have so far 256 = 576 + 484 - 1056
jimthompson5910 (jim_thompson5910):
so it would be 256 = 576 + 484 - 1056*cos(T)
or 256 = 576 + 484 - 1056x
if you let x = cos(T)
OpenStudy (anonymous):
okay then add 576 + 484 ?
jimthompson5910 (jim_thompson5910):
yep
OpenStudy (anonymous):
then do I subtract from 256 ?
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