change into y=mx+b formula 2x+3y<6 5x-3y<15
2x + 3y < 6 3y < 6 - 2x OR 3y < -2x + 6 y < -2/3X + 6/3 y < -2/3X + 2 \[y = -\frac{ 2 }{ 3 } X + 2\] 5x - 3y <15 -3y < 15 - 5x OR -3y < -5x +15 y > 5/3 - 15/3 - Notice Inequality signs change when you divide/multiply a negative number across them \[y > \frac{ 5 }{ 3 } X - 5\]
thank you! where do i plug in (0,0) for a test point to graph?
I don't understand what you are asking.
the original equations? 2x+3y<6 & 5x-3y<15
What about them?
i have to graph the equation and shade. so my test point is (0,0)
does that get plugged into my original equations?
Do you know how to graph them?
yes
Why would you plug in the point (0,0) ?
(0,0) is called the origin. It's where The X-axis and Y-axis intersect. Neither one of these lines pass through the origin.
the two systems are linear inequalities. since the two lines don't pass through (0,0) you can use that as a test point to check that your equation is true. i just found it in my notes. so you plug in 2(0)+3(0)<6 0<6 is true. then you do 5(0)-3(0)<15 0<15 is also true so you shade everything that satisfies the equation through your test point.
Ah ok, nobody ever asks me to shade anymore, but I briefly remember that from many years ago.
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