Mathematics
8 Online
OpenStudy (anonymous):
f(x) ln|x^2-11|
Differentiate. (derivatives of logarithmic functions)
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OpenStudy (anonymous):
\[f'(x)=\frac{ 1 }{ x ^{2}-11 }2x\]
OpenStudy (anonymous):
=(2 x)/(-11+x^2)
OpenStudy (anonymous):
sorry guys there was a typo. not eleven but 1.
OpenStudy (anonymous):
can u show me the steps?
OpenStudy (anonymous):
do you know the chain rule ?
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OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
what it says ?
OpenStudy (anonymous):
are u asking what the chain rule is? not sure what you mean ...
OpenStudy (anonymous):
chain rule in differentiation
OpenStudy (anonymous):
if we want to differentiate a function (say f(x)),
in your case it is f(x)= ln|x^2-11|.
What will be the first step ?
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OpenStudy (anonymous):
i actually don't have the chain rule quite down. could you show me? also its number one instead of eleven. it was a typo
OpenStudy (anonymous):
let f(x)= ln|g(x)|
what did you get differentiating this
OpenStudy (anonymous):
2x?
OpenStudy (anonymous):
nopes. f'(x)={1/g(x)} g'(x)
put g(x)= x^2-1
OpenStudy (anonymous):
then what will be the g'(x) ?
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OpenStudy (anonymous):
1/2x * 2x
OpenStudy (anonymous):
wouldn't g'x just be 2x because x^2 = 2x and -1 = 0?
OpenStudy (anonymous):
right
OpenStudy (anonymous):
but our f'(x) is
\[f(x)=\frac{ 1 }{ g(x) }g'(x)\]
OpenStudy (anonymous):
@sohrinny Do you still need help or are you clear on what is to be done?
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OpenStudy (anonymous):
no i still need help