Question

One pipe can fill a swimming pool in 5 hours less than another. Together they fill the swimming pool in 5 hours. How long would it take each pipe to fill the tank alone?

Answer 1

let one of th pipe take 'x' hrs then other would take (x-5) hrs, right ?
Now, do you know how to make an equation of this : 'Together they fill the swimming pool in 5 hours.' ??

Answer 2

5=(x-5)+5

Answer 3

so x =5

Answer 4

nope, if A can do the work in y days , B can do the work in z days then they both together will do the work in (1/y+1/z) days
so, here it'll be
\((1/x)+1/(x-5)=5\)
can you solve this ?

Answer 5

sorry, its \((1/x)+1/(x-5)=1/5\)

Answer 6

y is i 1/x? y division?

Answer 7

ok, if A can do the work in 'y' hrs,
then he will do (1/y) of the work in 1 hour , right ? got this ?
(we take unit time, like 1 hr, 1 day, ....)

Answer 8

one of the pipe take 'x' hrs to fill,
then that pipe would fill 1/x of the pool in 1 hr.

Answer 9

i see

Answer 10

other would take (x-5) hrs,
then other pipe would take 1/(x-5) of the pool in 1 hr.

Answer 11

then u would solve for x?

Answer 12

yup, solve for x in
1/x +1/(x-5) = 1/5

Answer 13

\[(15+-\sqrt{125})/2\]

Answer 14

yeah, i get the same weird answer :O

Answer 15

but the equation 1/x +1/(x-5) =1/5 is absolutely correct.

Answer 16

okay thnks

Answer 17

welcome ^_^