Question

Help please!!!!


Find a model for simple harmonic motion if the position at t = 0 is 2, the amplitude is 2 centimeters, and the period is 6 seconds.

Answer 1

any ideas @MaJosephine

Answer 2

any ideas @Noura11

Answer 3

It can be written like this :
\[x=a\cos(\omega t+\varphi)\]
And we have to determine a, omega and phi.
a is the amplitude so :
\[a=2 cm=0.02m\]
the periode T is :
\[T=6s\]
but we have :
\[\omega =\frac{2\pi}T\]
so :
\[\omega=\frac{\pi}{3} rd/s\]

Answer 4

ok i think im following you so far.

Answer 5

Now to find phi we have that at t=0 , x= 2 cm
So :
\[0.02=0.02\cos \varphi\]
so :
\[\cos\varphi=1\]
and then :
\[\varphi=0\]
So the motion time equation is :
\[x=0.02\cos\frac{\pi t}{3}\]

Answer 6

okwhy .oo2 and not just 2

Answer 7

nvrmnd i got it thank you

Answer 8

Because, you have to put the length in meters not in centimeters !