Question

giving best answer or fanning
solve x+3/(3x)>2

Answer 1

cross multiply

Answer 2

\[x+3>6x\]

Answer 3

not actually, how do you know whether x is positive or negative, and whether to switch signs or not ?

Answer 4

the question is \(\dfrac{x+3}{3x}>2\)
right ?

Answer 5

cant we write x>-3/5?

Answer 6

yes that is the question @hartnn

Answer 7

then the only way to do that is to break up,
\(\dfrac{x}{3x}+\dfrac{3}{3x}>2\)

Answer 8

then 'x' gets cancelled,
and you can move 1/3 to right side because its a constant, not a variable

Answer 9

@Alexis2332 try to contibue ?

Answer 10

**continue

Answer 11

not 100% what to do next

Answer 12

\(\dfrac{1}{3}+\dfrac{3}{3x}>2\)
subtract 1/3 from both sides, what u get ?

Answer 13

3/3x > 1 1/3

Answer 14

2-1/3 = 1 1/3 or 1 2/3 ??

Answer 15

2-1/3 = (2*3-1 ) /3 = 5/3 = (3+2)/3 = 1 2/3
got this ?

Answer 16

yes got that

Answer 17

ok, also 3/3x simplifies to 1/3 (the 3's cancel out)
and lets keep that as 5/3 , so we have
\(\dfrac{1}{x}>\dfrac{5}{3}\)
now just take the reciprocal, and flip the sign!
like if \(\dfrac{a}{b}>\dfrac{c}{d} \implies \dfrac{b}{a}>\dfrac{d}{c} \)
so ,what about
\(\dfrac{1}{x}>\dfrac{5}{3} \)
???

Answer 18

****
\(\dfrac{a}{b}>\dfrac{c}{d} \implies \dfrac{b}{a}<\dfrac{d}{c}\)

Answer 19

x/1 < 3/5

Answer 20

x < 3/5
correct

Answer 21

and to make it more accurate, \(0<x<3/5\)

Answer 22

oh okay I got it, thanks!

Answer 23

welcome ^_^