calculate the change in the melting ice if the pressure is increased from 1 to 2 atmospheric pressure. (specific volume of ice and water are 1.0908x10^-3 and 1.001x10^-3m/kg and latent heat is 3.4x10^-5j/kg and at normal atmospheric pressure at 0 degree celcius)

Question

anonymous · Answer

first u convert volume of water into mass by the help of formula m=density*volume. d=1000kg/m3.then find $$DeltaQ =mLf $$
CHANGE IN MELTING=$$DeltaS=mLf \T$$

anonymous · Answer

must change temp into kelvin

anonymous · Answer

thank you. am trying to solve it but i dont know what the F and the T  stands for

anonymous · Answer

Lf is latent heat
 and T is temperature

anonymous · Answer

alright