Question

how many 5 person committees are possible from a group of 8 people if both jim and mary must be on the committee

Answer 1

since both jim and mary are on the committee, you have only 6 people left to choose from, and 3 people to put in the committee
your job is therefore to compute 6 choose 2, sometimes written as \(_6C_3\) but mostly written as \(\binom{6}{3}\)

Answer 2

so the answer is 6/3?

Answer 3

use the formula :
nCr = n!/(r!(n-r)!)

here n = 6, and r = 3

Answer 4

i dont understand how to do this

Answer 5

the answer is 20 but i dont know how to get it